day 24 part 1 but too slow

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Felix Van der Jeugt 2021-12-26 12:00:57 +01:00
parent 60ed6981b8
commit 0b6b3ede21
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120
day24/part1.lua Executable file
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@ -0,0 +1,120 @@
#!/usr/bin/env luajit
require("utils")
local function trunc(a)
if a < 0 then
return math.ceil(a)
else
return math.floor(a)
end
end
local map = { w=1, x=2, y=3, z=4 }
local instructions = {}
for line in io.lines(arg[3]) do
local inst, a1, a2 = unpack(split(line, " "))
if inst == "inp" then
table.insert(instructions, function(memory, input)
local i, o = 9, memory[a1]
return function()
if i > 1 then
i = i - 1
memory[a1] = i
return input * 10 + i
else
memory[a1] = o
end
end
end)
elseif inst == "add" then
table.insert(instructions, function(memory, input)
local done, o = false, memory[a1]
return function()
if not done then
memory[a1] = memory[a1] + (memory[a2] or tonumber(a2))
done = true
return input
else
memory[a1] = o
end
end
end)
elseif inst == "mul" then
table.insert(instructions, function(memory, input)
local done, o = false, memory[a1]
return function()
if not done then
memory[a1] = memory[a1] * (memory[a2] or tonumber(a2))
done = true
return input
else
memory[a1] = o
end
end
end)
elseif inst == "div" then
table.insert(instructions, function(memory, input)
local done, o = false, memory[a1]
return function()
if not done and (memory[a2] or tonumber(a2)) ~= 0 then
memory[a1] = trunc(memory[a1] / (memory[a2] or tonumber(a2)))
done = true
return input
else
memory[a1] = o
end
end
end)
elseif inst == "mod" then
table.insert(instructions, function(memory, input)
local done, o = false, memory[a1]
return function()
local v = memory[a2] or tonumber(a2)
if not done and memory[a1] >= 0 and v > 0 then
memory[a1] = memory[a1] % v
done = true
return input
else
memory[a1] = o
end
end
end)
elseif inst == "eql" then
table.insert(instructions, function(memory, input)
local done, o = false, memory[a1]
return function()
if not done then
if memory[a1] == (memory[a2] or tonumber(a2)) then
memory[a1] = 1
else
memory[a1] = 0
end
done = true
return input
else
memory[a1] = o
end
end
end)
end
end
local maximum = 0
local function backtrack(i, memory, input)
if i == #instructions then
if memory.z == 0 and input > maximum then
print(input)
print(os.date())
maximum = input
end
else
-- io.write("i "..tostring(i).." ")
-- printtable(memory)
for newinput in instructions[i](memory, input) do
backtrack(i + 1, memory, newinput)
end
end
end
backtrack(1, { w=0, x=0, y=0, z=0 }, 0)
print(maximum)